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NOT 481-2002-en

REF. 5029 EXAMPLE. - T03 AND T05 POWER CALCULATIONS

Description: 






if you are using 15vdc to power both t05 and t03 modules, you must take into account that there are only 35.4 watts available for all of them.

this means that the 15vdc-power source could not be able to power all the t03 modules (plus possible additional mast amplifiers) if the consumption of the t05 modules were too high.

in these conditions the psu might burn.



example:

5 t03 amplifiers + 5 t05 modulators

case a)

5 * 5083 => power (t03 with 24 vdc) = 5 * 1.56 = 7.8 w

5 x 5844 => power (t05 with 15 vdc) = 5 x 4.28 = 21.4 w

this system would be perfectly possible because:

  • power (t03 with 24 vdc) less than 13.2 w and,
  • power (t05 with 15 vdc) less than 35.4 w.

case b)

4 x 5083 => power (t03 w/o mast amp.) = 4 x 1.56 = 6.24 w

1 x 5083 => power (t03 with mast amp.) = 2.4 w

power (t03 with 24 vdc) = power (t03 w/o mast amp.) + power (t03 with mast amp.)

then,

power (t03 with 24 vdc) = 6.24 + 2.4 = 8.64 w

5 x 5844 => power (t05 with 15 vdc) = 5 x 4.28 = 21.4 w

again power (t03 with 24 vdc) less than 13.2 w and power (t03 with 24 vdc) less than 35.4 w

Id Anrterior: 
27
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